EngiRef / Formulas
Pump Power
Power required by pump
Pipe Flow
Source Details
Id
fluids-pump-power
Name
Pump Power
Discipline
fluids
Category
Pipe Flow
Latex
P = \frac{\rho g Q H}{\eta}
Description
Power required by pump
Conditions
Hydraulic power; efficiency η is a fraction between 0 and 1
Variables
[
{
"symbol": "P",
"name": "Power",
"unit": "W",
"siUnit": "W",
"imperialUnit": "hp"
},
{
"symbol": "ρ",
"name": "Fluid Density",
"unit": "kg/m³",
"siUnit": "kg/m³"
},
{
"symbol": "g",
"name": "Gravity",
"unit": "m/s²",
"siUnit": "m/s²"
},
{
"symbol": "Q",
"name": "Flow Rate",
"unit": "m³/s",
"siUnit": "m³/s",
"imperialUnit": "gpm"
},
{
"symbol": "H",
"name": "Head",
"unit": "m",
"siUnit": "m",
"imperialUnit": "ft"
},
{
"symbol": "η",
"name": "Efficiency",
"unit": "",
"siUnit": ""
}
]Solve For
P, Q, H, η
Tags
pump, power, head, flow
Is Custom
false