EngiRef / Formulas

Pump Power

Power required by pump

Pipe Flow

Source Details

Id

fluids-pump-power

Name

Pump Power

Discipline

fluids

Category

Pipe Flow

Latex

P = \frac{\rho g Q H}{\eta}

Description

Power required by pump

Conditions

Hydraulic power; efficiency η is a fraction between 0 and 1

Variables
[
  {
    "symbol": "P",
    "name": "Power",
    "unit": "W",
    "siUnit": "W",
    "imperialUnit": "hp"
  },
  {
    "symbol": "ρ",
    "name": "Fluid Density",
    "unit": "kg/m³",
    "siUnit": "kg/m³"
  },
  {
    "symbol": "g",
    "name": "Gravity",
    "unit": "m/s²",
    "siUnit": "m/s²"
  },
  {
    "symbol": "Q",
    "name": "Flow Rate",
    "unit": "m³/s",
    "siUnit": "m³/s",
    "imperialUnit": "gpm"
  },
  {
    "symbol": "H",
    "name": "Head",
    "unit": "m",
    "siUnit": "m",
    "imperialUnit": "ft"
  },
  {
    "symbol": "η",
    "name": "Efficiency",
    "unit": "",
    "siUnit": ""
  }
]
Solve For

P, Q, H, η

Tags

pump, power, head, flow

Is Custom

false